How To Find Data In MySQL Database And Display It In Html Table Using Php
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In this Php Tutorial You will see How You Can Make Search Input Text And Show Data With Input Text Value In Html Table Using MySQL Database And Php .
I Use In This Tutorial:
– NetBeans IDE .
– XAMPP .
– PhpMyAdmin .
Others Tutorials :
Get Select Option Value From MySQL Database Using Php
How To Populate Html Table From MySQL Database Using Php
How To Use Mysqli Num Rows In Php
How To Use Pdo Row Count In Php
Insert Update Delete Search Data In MySQL Database Using Php Part1
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great job…
thank you so much
thank u so much
Sir.
Can You Tell Me I Can Get Image After Search Like this, Please Sir help Me.
thanks bro
AUDIO
Got it, thank you sir!
i like
Clever as good.
Thank you so much sir!
Thanks for the codes It's a good start for me hope you post a lot of video tutorials regarding web development..
No error but the query doesnt fectch my data?
guest the difference
correct
$query = "SELECT * FROM `users` WHERE CONCAT(`id`, `first_name`, `last_name`, `mail`, `dob`) LIKE '%".$valueToSearch."%'";
wrong
$query = "SELECT * FROM `users` WHERE CONCAT('id', 'first_name', 'last_name', 'mail', 'dob') LIKE '%".$valueToSearch."%'";
thank you so much…
need help!!
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, bool given in /home/vol13_6/epizy.com/epiz_24632333/htdocs/searchcode.php on line 55
Any suggestions for autocomplete
hey guys. what's the problem with this ===
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, bool
What if needed to search from two or more tables without using joins ?
How to find the diffrence between 2 rows?
ty dude ^_^ i love u
Plz make a video on how to join search bar with selecting coloumn by select box
This isn't really a filtered search result, it is a backwards search by elimination. How about a page with only a search text box on it with a checkbox that when "checked" will filter out OR only include all the people named John from the database results when you click on a "submit" button.
Awesome! Thank you for your work. Mine worked with this change for the first query.
"SELECT * FROM tablename WHERE columnname LIKE '%$valueToSearch%'"
when I'm inserting the action in form tag then my code is not working(not even else condition) and without action at least my else is working. I tried a lots of things with this code but nothing is working. please help me out…!
can you provide code for textbox,dropdown,dates(from,to) all at a time with single FILTER button.
php_html_table_data_filter.php ????
it work. thanks you
I am getting "Object not found" when clicking the search button. Any help?
This SQL code is very slow & unsecured.
Any SQL database can not use index for performence. Please use for teaching good variant for search, as possible use ( first_name like '' or last_name like '' + detect if (is_number($_POST['valueToSearch']) (id like '' OR age like '%%')
ohh yes
thank you this was really great! you made it quite simple,
I want to ask is it much harder to add multiple filter fields so you can filter at the same time? wow i figured it out it took al ong time, thank u for this very helpful!
hey,
Thankyou for a nice code.
i want you ask about the sql query that i want to select the top results from table on user demand. can you please help me.
example – as i your data select top 5 record filter by age column .
i am try this —
$query = "SELECT * FROM `users` ORDER BY count DESC LIKE '".$valueToSearch."' ";
but its not working .
please help me.
THANK YOU SOOOOO MUCH!!
All Good
If you are facing any issues regarding mysqli_fetch_array(),
just remove the single quote from the query you are using
e-g "SELECT 'patient_id', 'fname, lname', 'gender','dob','address' from patient ";
TO
"SELECT patient_id, fname, lname, gender,dob,address from patient ";
please how to search with adoquery in 2 table with edit delphi
Php_search_in_mysql_database.php was not found on this server
thank you so much it really helped me in doing my task to get job thanks a lot 🙂
If anyone of you guys encounter a problem saying "Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean…….."
all you have to do is erase or delete the single quote on residents on variable $query
instead of
$query = "SELECT * FROM 'residents'";
remove the single quote like this
$query = "SELECT * FROM residents";
and that will fix your problem 🙂
Thanks a lot , it does work !!!
Good show Dear
why mine when enter value the result is nothing just head of the table only
Thanks it works 🙂
for those people who has problems on mysqli_fetch_array() just add <form action="" method="post"><body>……..</body></form> and don't forget the CONCAT on the sql statement.
can you send me the complete workign code pleaes?
Please reply :'(